11001313233101 has 2 divisors, whose sum is σ = 11001313233102. Its totient is φ = 11001313233100.

The previous prime is 11001313233091. The next prime is 11001313233121. The reversal of 11001313233101 is 10133231310011.

It is an a-pointer prime, because the next prime (11001313233121) can be obtained adding 11001313233101 to its sum of digits (20).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9192963360100 + 1808349873001 = 3031990^2 + 1344749^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11001313233101 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11001313233121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500656616550 + 5500656616551.

It is an arithmetic number, because the mean of its divisors is an integer number (5500656616551).

Almost surely, 2^{11001313233101} is an apocalyptic number.

It is an amenable number.

11001313233101 is a deficient number, since it is larger than the sum of its proper divisors (1).

11001313233101 is an equidigital number, since it uses as much as digits as its factorization.

11001313233101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 11001313233101 its reverse (10133231310011), we get a palindrome (21134544543112).

The spelling of 11001313233101 in words is "eleven trillion, one billion, three hundred thirteen million, two hundred thirty-three thousand, one hundred one".