Base | Representation |
---|---|
bin | 110011001110101001… |
… | …1000110010111010000 |
3 | 101111222000021012222120 |
4 | 1212131103012113100 |
5 | 3300301340241422 |
6 | 122312300534240 |
7 | 10643141605506 |
oct | 1463523062720 |
9 | 344860235876 |
10 | 110013212112 |
11 | 42724654611 |
12 | 193a3251380 |
13 | a4b317481b |
14 | 5478c62676 |
15 | 2cdd35745c |
hex | 199d4c65d0 |
110013212112 has 20 divisors (see below), whose sum is σ = 284200798080. Its totient is φ = 36671070688.
The previous prime is 110013212107. The next prime is 110013212161. The reversal of 110013212112 is 211212310011.
It is a junction number, because it is equal to n+sod(n) for n = 110013212091 and 110013212100.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1145970912 + ... + 1145971007.
It is an arithmetic number, because the mean of its divisors is an integer number (14210039904).
Almost surely, 2110013212112 is an apocalyptic number.
110013212112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
110013212112 is an abundant number, since it is smaller than the sum of its proper divisors (174187585968).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
110013212112 is a wasteful number, since it uses less digits than its factorization.
110013212112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2291941930 (or 2291941924 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 110013212112 its reverse (211212310011), we get a palindrome (321225522123).
The spelling of 110013212112 in words is "one hundred ten billion, thirteen million, two hundred twelve thousand, one hundred twelve".
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