11001322551340 has 24 divisors (see below), whose sum is σ = 25203029845392. Its totient is φ = 4000480927680.

The previous prime is 11001322551293. The next prime is 11001322551341. The reversal of 11001322551340 is 4315522310011.

It is a junction number, because it is equal to n+sod(n) for n = 11001322551299 and 11001322551308.

It is not an unprimeable number, because it can be changed into a prime (11001322551341) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25003005579 + ... + 25003006018.

It is an arithmetic number, because the mean of its divisors is an integer number (1050126243558).

Almost surely, 2^{11001322551340} is an apocalyptic number.

11001322551340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

11001322551340 is an abundant number, since it is smaller than the sum of its proper divisors (14201707294052).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11001322551340 is a wasteful number, since it uses less digits than its factorization.

11001322551340 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50006011617 (or 50006011615 counting only the distinct ones).

The product of its (nonzero) digits is 3600, while the sum is 28.

Adding to 11001322551340 its reverse (4315522310011), we get a palindrome (15316844861351).

The spelling of 11001322551340 in words is "eleven trillion, one billion, three hundred twenty-two million, five hundred fifty-one thousand, three hundred forty".