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1100133221027 is a prime number
BaseRepresentation
bin10000000000100101000…
…011001100001010100011
310220011122011202002121212
4100000211003030022203
5121011033101033102
62201221052540335
7142324220042021
oct20004503141243
93804564662555
101100133221027
11394622582a15
121592684816ab
137c985580b99
143b365065711
151d93c518c52
hex100250cc2a3

1100133221027 has 2 divisors, whose sum is σ = 1100133221028. Its totient is φ = 1100133221026.

The previous prime is 1100133220939. The next prime is 1100133221039. The reversal of 1100133221027 is 7201223310011.

It is a strong prime.

It is an emirp because it is prime and its reverse (7201223310011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1100133221027 - 210 = 1100133220003 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1100133220993 and 1100133221011.

It is not a weakly prime, because it can be changed into another prime (1100133821027) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550066610513 + 550066610514.

It is an arithmetic number, because the mean of its divisors is an integer number (550066610514).

Almost surely, 21100133221027 is an apocalyptic number.

1100133221027 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100133221027 is an equidigital number, since it uses as much as digits as its factorization.

1100133221027 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 504, while the sum is 23.

Adding to 1100133221027 its reverse (7201223310011), we get a palindrome (8301356531038).

The spelling of 1100133221027 in words is "one trillion, one hundred billion, one hundred thirty-three million, two hundred twenty-one thousand, twenty-seven".