Base | Representation |
---|---|
bin | 11001000000111001111101… |
… | …101101000111110111001111 |
3 | 112102112011211002110101021111 |
4 | 121000321331231013313033 |
5 | 103404424421213103211 |
6 | 1025551243040112451 |
7 | 32113130432633356 |
oct | 3100717555076717 |
9 | 472464732411244 |
10 | 110013401300431 |
11 | 3206546aa995a2 |
12 | 10409401605727 |
13 | 49502b084b625 |
14 | 1d24969acc99d |
15 | caba7aed3421 |
hex | 640e7db47dcf |
110013401300431 has 2 divisors, whose sum is σ = 110013401300432. Its totient is φ = 110013401300430.
The previous prime is 110013401300393. The next prime is 110013401300437. The reversal of 110013401300431 is 134003104310011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 110013401300431 - 229 = 110012864429519 is a prime.
It is a super-2 number, since 2×1100134013004312 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110013401300437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55006700650215 + 55006700650216.
It is an arithmetic number, because the mean of its divisors is an integer number (55006700650216).
Almost surely, 2110013401300431 is an apocalyptic number.
110013401300431 is a deficient number, since it is larger than the sum of its proper divisors (1).
110013401300431 is an equidigital number, since it uses as much as digits as its factorization.
110013401300431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 110013401300431 its reverse (134003104310011), we get a palindrome (244016505610442).
The spelling of 110013401300431 in words is "one hundred ten trillion, thirteen billion, four hundred one million, three hundred thousand, four hundred thirty-one".
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