Base | Representation |
---|---|
bin | 11001000000111001111101… |
… | …101101000111110111010101 |
3 | 112102112011211002110101021201 |
4 | 121000321331231013313111 |
5 | 103404424421213103222 |
6 | 1025551243040112501 |
7 | 32113130432633365 |
oct | 3100717555076725 |
9 | 472464732411251 |
10 | 110013401300437 |
11 | 3206546aa995a8 |
12 | 10409401605731 |
13 | 49502b084b62b |
14 | 1d24969acc9a5 |
15 | caba7aed3427 |
hex | 640e7db47dd5 |
110013401300437 has 2 divisors, whose sum is σ = 110013401300438. Its totient is φ = 110013401300436.
The previous prime is 110013401300431. The next prime is 110013401300477. The reversal of 110013401300437 is 734003104310011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 106198981373521 + 3814419926916 = 10305289^2 + 1953054^2 .
It is a cyclic number.
It is not a de Polignac number, because 110013401300437 - 227 = 110013267082709 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110013401300431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55006700650218 + 55006700650219.
It is an arithmetic number, because the mean of its divisors is an integer number (55006700650219).
Almost surely, 2110013401300437 is an apocalyptic number.
It is an amenable number.
110013401300437 is a deficient number, since it is larger than the sum of its proper divisors (1).
110013401300437 is an equidigital number, since it uses as much as digits as its factorization.
110013401300437 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3024, while the sum is 28.
Adding to 110013401300437 its reverse (734003104310011), we get a palindrome (844016505610448).
The spelling of 110013401300437 in words is "one hundred ten trillion, thirteen billion, four hundred one million, three hundred thousand, four hundred thirty-seven".
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