Base | Representation |
---|---|
bin | 10100011111011101… |
… | …10010100111110111 |
3 | 1001101200222002201222 |
4 | 22033232302213313 |
5 | 140012320424310 |
6 | 5015352540555 |
7 | 536423603465 |
oct | 121756624767 |
9 | 31350862658 |
10 | 11001342455 |
11 | 4735a75464 |
12 | 21703b175b |
13 | 10642a76bc |
14 | 76513d835 |
15 | 445c57055 |
hex | 28fbb29f7 |
11001342455 has 4 divisors (see below), whose sum is σ = 13201610952. Its totient is φ = 8801073960.
The previous prime is 11001342409. The next prime is 11001342463. The reversal of 11001342455 is 55424310011.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 55424310011 = 7 ⋅7917758573.
It is not a de Polignac number, because 11001342455 - 210 = 11001341431 is a prime.
It is a super-3 number, since 3×110013424553 (a number of 31 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1100134241 + ... + 1100134250.
It is an arithmetic number, because the mean of its divisors is an integer number (3300402738).
Almost surely, 211001342455 is an apocalyptic number.
11001342455 is a deficient number, since it is larger than the sum of its proper divisors (2200268497).
11001342455 is an equidigital number, since it uses as much as digits as its factorization.
11001342455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2200268496.
The product of its (nonzero) digits is 2400, while the sum is 26.
Adding to 11001342455 its reverse (55424310011), we get a palindrome (66425652466).
The spelling of 11001342455 in words is "eleven billion, one million, three hundred forty-two thousand, four hundred fifty-five".
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