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110014103240141 is a prime number
BaseRepresentation
bin11001000000111010100111…
…100010110011110111001101
3112102112020122000021121112112
4121000322213202303313031
5103404432340412141031
61025551440433113405
732113154015214002
oct3100724742636715
9472466560247475
10110014103240141
11320657a0243261
12104095786b8865
1349503930b9879
141d249d500d8a9
15cababc93a62b
hex640ea78b3dcd

110014103240141 has 2 divisors, whose sum is σ = 110014103240142. Its totient is φ = 110014103240140.

The previous prime is 110014103240081. The next prime is 110014103240149. The reversal of 110014103240141 is 141042301410011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 110013457012900 + 646227241 = 10488730^2 + 25421^2 .

It is an emirp because it is prime and its reverse (141042301410011) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-110014103240141 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110014103240149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55007051620070 + 55007051620071.

It is an arithmetic number, because the mean of its divisors is an integer number (55007051620071).

Almost surely, 2110014103240141 is an apocalyptic number.

It is an amenable number.

110014103240141 is a deficient number, since it is larger than the sum of its proper divisors (1).

110014103240141 is an equidigital number, since it uses as much as digits as its factorization.

110014103240141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384, while the sum is 23.

Adding to 110014103240141 its reverse (141042301410011), we get a palindrome (251056404650152).

The spelling of 110014103240141 in words is "one hundred ten trillion, fourteen billion, one hundred three million, two hundred forty thousand, one hundred forty-one".