1100200112323 has 4 divisors (see below), whose sum is σ = 1184830890208. Its totient is φ = 1015569334440.

The previous prime is 1100200112287. The next prime is 1100200112351. The reversal of 1100200112323 is 3232110020011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1100200112323 - 2¹³ = 1100200104131 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1100200112297 and 1100200112306.

It is not an unprimeable number, because it can be changed into a prime (1100200112023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42315388923 + ... + 42315388948.

It is an arithmetic number, because the mean of its divisors is an integer number (296207722552).

Almost surely, 2^{1100200112323} is an apocalyptic number.

1100200112323 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1100200112323 is a deficient number, since it is larger than the sum of its proper divisors (84630777885).

1100200112323 is an equidigital number, since it uses as much as digits as its factorization.

1100200112323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 84630777884.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 1100200112323 its reverse (3232110020011), we get a palindrome (4332310132334).

The spelling of 1100200112323 in words is "one trillion, one hundred billion, two hundred million, one hundred twelve thousand, three hundred twenty-three".