Base | Representation |
---|---|
bin | 1010000000011001101001… |
… | …1010111111001101111011 |
3 | 1102221210002102210101010002 |
4 | 2200012122122333031323 |
5 | 2420224100003323003 |
6 | 35222125553343215 |
7 | 2213603603042153 |
oct | 240063232771573 |
9 | 42853072711102 |
10 | 11002002011003 |
11 | 3561a1734a463 |
12 | 1298318267b0b |
13 | 61a63b123853 |
14 | 2a06dd3d5763 |
15 | 1412c2317a88 |
hex | a019a6bf37b |
11002002011003 has 2 divisors, whose sum is σ = 11002002011004. Its totient is φ = 11002002011002.
The previous prime is 11002002010997. The next prime is 11002002011009. The reversal of 11002002011003 is 30011020020011.
It is a balanced prime because it is at equal distance from previous prime (11002002010997) and next prime (11002002011009).
It is a cyclic number.
It is not a de Polignac number, because 11002002011003 - 26 = 11002002010939 is a prime.
It is a super-2 number, since 2×110020020110032 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11002002011009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5501001005501 + 5501001005502.
It is an arithmetic number, because the mean of its divisors is an integer number (5501001005502).
Almost surely, 211002002011003 is an apocalyptic number.
11002002011003 is a deficient number, since it is larger than the sum of its proper divisors (1).
11002002011003 is an equidigital number, since it uses as much as digits as its factorization.
11002002011003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 11.
Adding to 11002002011003 its reverse (30011020020011), we get a palindrome (41013022031014).
The spelling of 11002002011003 in words is "eleven trillion, two billion, two million, eleven thousand, three".
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