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1100201310103 = 7157171615729
BaseRepresentation
bin10000000000101001000…
…110111011011110010111
310220011210220212101021111
4100000221012323132113
5121011203013410403
62201231524155451
7142326004556320
oct20005106733627
93804726771244
101100201310103
11394657a59285
12159287238b87
137c99670098c
143b37010b447
151d9434b856d
hex100291bb797

1100201310103 has 4 divisors (see below), whose sum is σ = 1257372925840. Its totient is φ = 943029694368.

The previous prime is 1100201310067. The next prime is 1100201310163. The reversal of 1100201310103 is 3010131020011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1100201310103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1100201310163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 78585807858 + ... + 78585807871.

It is an arithmetic number, because the mean of its divisors is an integer number (314343231460).

Almost surely, 21100201310103 is an apocalyptic number.

1100201310103 is a deficient number, since it is larger than the sum of its proper divisors (157171615737).

1100201310103 is an equidigital number, since it uses as much as digits as its factorization.

1100201310103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 157171615736.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 1100201310103 its reverse (3010131020011), we get a palindrome (4110332330114).

The spelling of 1100201310103 in words is "one trillion, one hundred billion, two hundred one million, three hundred ten thousand, one hundred three".

Divisors: 1 7 157171615729 1100201310103