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1100202022022 = 21610393415949
BaseRepresentation
bin10000000000101001001…
…001101001010010000110
310220011210222012112211212
4100000221021221102012
5121011203204201042
62201231551331422
7142326013613015
oct20005111512206
93804728175755
101100202022022
113946583a5144
12159287520b72
137c9968bca2c
143b370254a7c
151d9435a9482
hex10029269486

1100202022022 has 8 divisors (see below), whose sum is σ = 1650313764000. Its totient is φ = 550097434024.

The previous prime is 1100202021979. The next prime is 1100202022033. The reversal of 1100202022022 is 2202202020011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×11002020220222 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1100202021988 and 1100202022006.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1385897 + ... + 2030052.

It is an arithmetic number, because the mean of its divisors is an integer number (206289220500).

Almost surely, 21100202022022 is an apocalyptic number.

1100202022022 is a deficient number, since it is larger than the sum of its proper divisors (550111741978).

1100202022022 is a wasteful number, since it uses less digits than its factorization.

1100202022022 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3576990.

The product of its (nonzero) digits is 64, while the sum is 14.

Adding to 1100202022022 its reverse (2202202020011), we get a palindrome (3302404042033).

The spelling of 1100202022022 in words is "one trillion, one hundred billion, two hundred two million, twenty-two thousand, twenty-two".

Divisors: 1 2 161039 322078 3415949 6831898 550101011011 1100202022022