Base | Representation |
---|---|
bin | 110011001110110110… |
… | …1110011010100110011 |
3 | 101111222111102212001101 |
4 | 1212131231303110303 |
5 | 3300310133241034 |
6 | 122313110545231 |
7 | 10643255241424 |
oct | 1463555632463 |
9 | 344874385041 |
10 | 110020212019 |
11 | 427285a5763 |
12 | 193a5668217 |
13 | a4b4755993 |
14 | 5479b6564b |
15 | 2cddc8b514 |
hex | 199db73533 |
110020212019 has 2 divisors, whose sum is σ = 110020212020. Its totient is φ = 110020212018.
The previous prime is 110020212011. The next prime is 110020212023. The reversal of 110020212019 is 910212020011.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 110020212019 - 23 = 110020212011 is a prime.
It is a super-3 number, since 3×1100202120193 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 110020211987 and 110020212005.
It is not a weakly prime, because it can be changed into another prime (110020212011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55010106009 + 55010106010.
It is an arithmetic number, because the mean of its divisors is an integer number (55010106010).
Almost surely, 2110020212019 is an apocalyptic number.
110020212019 is a deficient number, since it is larger than the sum of its proper divisors (1).
110020212019 is an equidigital number, since it uses as much as digits as its factorization.
110020212019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 19.
The spelling of 110020212019 in words is "one hundred ten billion, twenty million, two hundred twelve thousand, nineteen".
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