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11002101133 is a prime number
BaseRepresentation
bin10100011111100011…
…01011110110001101
31001101202101122110011
422033301223312031
5140013014214013
65015421113221
7536433213412
oct121761536615
931352348404
1011002101133
114736443471
1221706b8811
1310644b1b1a
1476529a109
15445d56c3d
hex28fc6bd8d

11002101133 has 2 divisors, whose sum is σ = 11002101134. Its totient is φ = 11002101132.

The previous prime is 11002101127. The next prime is 11002101161. The reversal of 11002101133 is 33110120011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10970886564 + 31214569 = 104742^2 + 5587^2 .

It is an emirp because it is prime and its reverse (33110120011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11002101133 - 29 = 11002100621 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11002101163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5501050566 + 5501050567.

It is an arithmetic number, because the mean of its divisors is an integer number (5501050567).

Almost surely, 211002101133 is an apocalyptic number.

It is an amenable number.

11002101133 is a deficient number, since it is larger than the sum of its proper divisors (1).

11002101133 is an equidigital number, since it uses as much as digits as its factorization.

11002101133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 11002101133 its reverse (33110120011), we get a palindrome (44112221144).

The spelling of 11002101133 in words is "eleven billion, two million, one hundred one thousand, one hundred thirty-three".