Base | Representation |
---|---|
bin | 10100011111100011… |
… | …01011110110001101 |
3 | 1001101202101122110011 |
4 | 22033301223312031 |
5 | 140013014214013 |
6 | 5015421113221 |
7 | 536433213412 |
oct | 121761536615 |
9 | 31352348404 |
10 | 11002101133 |
11 | 4736443471 |
12 | 21706b8811 |
13 | 10644b1b1a |
14 | 76529a109 |
15 | 445d56c3d |
hex | 28fc6bd8d |
11002101133 has 2 divisors, whose sum is σ = 11002101134. Its totient is φ = 11002101132.
The previous prime is 11002101127. The next prime is 11002101161. The reversal of 11002101133 is 33110120011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10970886564 + 31214569 = 104742^2 + 5587^2 .
It is an emirp because it is prime and its reverse (33110120011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11002101133 - 29 = 11002100621 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11002101163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5501050566 + 5501050567.
It is an arithmetic number, because the mean of its divisors is an integer number (5501050567).
Almost surely, 211002101133 is an apocalyptic number.
It is an amenable number.
11002101133 is a deficient number, since it is larger than the sum of its proper divisors (1).
11002101133 is an equidigital number, since it uses as much as digits as its factorization.
11002101133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 11002101133 its reverse (33110120011), we get a palindrome (44112221144).
The spelling of 11002101133 in words is "eleven billion, two million, one hundred one thousand, one hundred thirty-three".
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