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1100210210207 is a prime number
BaseRepresentation
bin10000000000101001101…
…000111000010110011111
310220011211112121112220222
4100000221220320112133
5121011212303211312
62201232443031555
7142326143325203
oct20005150702637
93804745545828
101100210210207
11394661a88039
1215928a20b5bb
137c9984c8a04
143b371386b03
151d944175672
hex10029a3859f

1100210210207 has 2 divisors, whose sum is σ = 1100210210208. Its totient is φ = 1100210210206.

The previous prime is 1100210210173. The next prime is 1100210210221. The reversal of 1100210210207 is 7020120120011.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1100210210207 - 230 = 1099136468383 is a prime.

It is a super-2 number, since 2×11002102102072 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1100210210227) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550105105103 + 550105105104.

It is an arithmetic number, because the mean of its divisors is an integer number (550105105104).

Almost surely, 21100210210207 is an apocalyptic number.

1100210210207 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100210210207 is an equidigital number, since it uses as much as digits as its factorization.

1100210210207 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 56, while the sum is 17.

Adding to 1100210210207 its reverse (7020120120011), we get a palindrome (8120330330218).

The spelling of 1100210210207 in words is "one trillion, one hundred billion, two hundred ten million, two hundred ten thousand, two hundred seven".