11002121000121 has 4 divisors (see below), whose sum is σ = 14669494666832. Its totient is φ = 7334747333412.

The previous prime is 11002121000113. The next prime is 11002121000153. The reversal of 11002121000121 is 12100012120011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 11002121000121 - 2³ = 11002121000113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11002121000097 and 11002121000106.

It is not an unprimeable number, because it can be changed into a prime (11002126000121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1833686833351 + ... + 1833686833356.

It is an arithmetic number, because the mean of its divisors is an integer number (3667373666708).

Almost surely, 2^{11002121000121} is an apocalyptic number.

It is an amenable number.

11002121000121 is a deficient number, since it is larger than the sum of its proper divisors (3667373666711).

11002121000121 is an equidigital number, since it uses as much as digits as its factorization.

11002121000121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3667373666710.

The product of its (nonzero) digits is 8, while the sum is 12.

Adding to 11002121000121 its reverse (12100012120011), we get a palindrome (23102133120132).

The spelling of 11002121000121 in words is "eleven trillion, two billion, one hundred twenty-one million, one hundred twenty-one", and thus it is an aban number.