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11002201207 is a prime number
BaseRepresentation
bin10100011111100100…
…00100010001110111
31001101202120201201121
422033302010101313
5140013030414312
65015423204411
7536434111234
oct121762042167
931352521647
1011002201207
114736501678
122170746707
13106451853a
147652c478b
15445d76707
hex28fc84477

11002201207 has 2 divisors, whose sum is σ = 11002201208. Its totient is φ = 11002201206.

The previous prime is 11002201183. The next prime is 11002201229. The reversal of 11002201207 is 70210220011.

11002201207 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11002201207 - 215 = 11002168439 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11002201297) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5501100603 + 5501100604.

It is an arithmetic number, because the mean of its divisors is an integer number (5501100604).

Almost surely, 211002201207 is an apocalyptic number.

11002201207 is a deficient number, since it is larger than the sum of its proper divisors (1).

11002201207 is an equidigital number, since it uses as much as digits as its factorization.

11002201207 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 56, while the sum is 16.

Adding to 11002201207 its reverse (70210220011), we get a palindrome (81212421218).

The spelling of 11002201207 in words is "eleven billion, two million, two hundred one thousand, two hundred seven".