11002211001983 has 2 divisors, whose sum is σ = 11002211001984. Its totient is φ = 11002211001982.

The previous prime is 11002211001961. The next prime is 11002211002019. The reversal of 11002211001983 is 38910011220011.

It is a happy number.

11002211001983 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11002211001983 - 2⁴² = 6604164490879 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11002271001983) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5501105500991 + 5501105500992.

It is an arithmetic number, because the mean of its divisors is an integer number (5501105500992).

Almost surely, 2^{11002211001983} is an apocalyptic number.

11002211001983 is a deficient number, since it is larger than the sum of its proper divisors (1).

11002211001983 is an equidigital number, since it uses as much as digits as its factorization.

11002211001983 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864, while the sum is 29.

Adding to 11002211001983 its reverse (38910011220011), we get a palindrome (49912222221994).

The spelling of 11002211001983 in words is "eleven trillion, two billion, two hundred eleven million, one thousand, nine hundred eighty-three".