Base | Representation |
---|---|
bin | 1010000000011010100110… |
… | …0000001001001111001011 |
3 | 1102221210202001212121120211 |
4 | 2200012221200021033023 |
5 | 2420230104241133003 |
6 | 35222211032301551 |
7 | 2213613064431511 |
oct | 240065140111713 |
9 | 42853661777524 |
10 | 11002255021003 |
11 | 3562037149634 |
12 | 1298388b418b7 |
13 | 61a67b67b2cc |
14 | 2a0724c564b1 |
15 | 1412d964396d |
hex | a01a98093cb |
11002255021003 has 6 divisors (see below), whose sum is σ = 11611798235844. Its totient is φ = 10423188966924.
The previous prime is 11002255020941. The next prime is 11002255021019. The reversal of 11002255021003 is 30012055220011.
It is not a de Polignac number, because 11002255021003 - 213 = 11002255012811 is a prime.
It is a super-3 number, since 3×110022550210033 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11002255021073) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 15238580001 + ... + 15238580722.
It is an arithmetic number, because the mean of its divisors is an integer number (1935299705974).
Almost surely, 211002255021003 is an apocalyptic number.
11002255021003 is a deficient number, since it is larger than the sum of its proper divisors (609543214841).
11002255021003 is an equidigital number, since it uses as much as digits as its factorization.
11002255021003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 30477160761 (or 30477160742 counting only the distinct ones).
The product of its (nonzero) digits is 600, while the sum is 22.
The spelling of 11002255021003 in words is "eleven trillion, two billion, two hundred fifty-five million, twenty-one thousand, three".
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