Base | Representation |
---|---|
bin | 10000000000101011100… |
… | …000000001100101100101 |
3 | 10220011220201101100111111 |
4 | 100000223200001211211 |
5 | 121011243302140143 |
6 | 2201235520305021 |
7 | 142330002650335 |
oct | 20005340014545 |
9 | 3804821340444 |
10 | 1100241443173 |
11 | 39467867a904 |
12 | 159298772171 |
13 | 7c9a1b12c62 |
14 | 3b3755970c5 |
15 | 1d946c9499d |
hex | 1002b801965 |
1100241443173 has 2 divisors, whose sum is σ = 1100241443174. Its totient is φ = 1100241443172.
The previous prime is 1100241443111. The next prime is 1100241443183. The reversal of 1100241443173 is 3713441420011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1088896424004 + 11345019169 = 1043502^2 + 106513^2 .
It is a cyclic number.
It is not a de Polignac number, because 1100241443173 - 233 = 1091651508581 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1100241443183) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550120721586 + 550120721587.
It is an arithmetic number, because the mean of its divisors is an integer number (550120721587).
Almost surely, 21100241443173 is an apocalyptic number.
It is an amenable number.
1100241443173 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100241443173 is an equidigital number, since it uses as much as digits as its factorization.
1100241443173 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8064, while the sum is 31.
Adding to 1100241443173 its reverse (3713441420011), we get a palindrome (4813682863184).
The spelling of 1100241443173 in words is "one trillion, one hundred billion, two hundred forty-one million, four hundred forty-three thousand, one hundred seventy-three".
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