11002513131131 has 8 divisors (see below), whose sum is σ = 11191507104240. Its totient is φ = 10813602848128.

The previous prime is 11002513131121. The next prime is 11002513131199. The reversal of 11002513131131 is 13113131520011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11002513131131 is a prime.

It is a super-2 number, since 2×11002513131131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11002513131097 and 11002513131106.

It is not an unprimeable number, because it can be changed into a prime (11002513131121) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 20657306 + ... + 21183231.

It is an arithmetic number, because the mean of its divisors is an integer number (1398938388030).

Almost surely, 2^{11002513131131} is an apocalyptic number.

11002513131131 is a deficient number, since it is larger than the sum of its proper divisors (188993973109).

11002513131131 is an equidigital number, since it uses as much as digits as its factorization.

11002513131131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 41845053.

The product of its (nonzero) digits is 270, while the sum is 23.

Adding to 11002513131131 its reverse (13113131520011), we get a palindrome (24115644651142).

The spelling of 11002513131131 in words is "eleven trillion, two billion, five hundred thirteen million, one hundred thirty-one thousand, one hundred thirty-one".