Search a number
-
+
11003020034 = 25501510017
BaseRepresentation
bin10100011111101010…
…01100001100000010
31001101211010022221112
422033311030030002
5140013233120114
65015452523322
7536444061416
oct121765141402
931354108845
1011003020034
114736a10896
122170a80542
131064744156
14765458d46
15445e8913e
hex28fd4c302

11003020034 has 4 divisors (see below), whose sum is σ = 16504530054. Its totient is φ = 5501510016.

The previous prime is 11003020033. The next prime is 11003020043. The reversal of 11003020034 is 43002030011.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 43002030011 = 103417495437.

It can be written as a sum of positive squares in only one way, i.e., 10501125625 + 501894409 = 102475^2 + 22403^2 .

It is a super-2 number, since 2×110030200342 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (11003020033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2750755007 + ... + 2750755010.

Almost surely, 211003020034 is an apocalyptic number.

11003020034 is a deficient number, since it is larger than the sum of its proper divisors (5501510020).

11003020034 is an equidigital number, since it uses as much as digits as its factorization.

11003020034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5501510019.

The product of its (nonzero) digits is 72, while the sum is 14.

Adding to 11003020034 its reverse (43002030011), we get a palindrome (54005050045).

The spelling of 11003020034 in words is "eleven billion, three million, twenty thousand, thirty-four".

Divisors: 1 2 5501510017 11003020034