Base | Representation |
---|---|
bin | 10100011111101010… |
… | …01100001100000001 |
3 | 1001101211010022221111 |
4 | 22033311030030001 |
5 | 140013233120113 |
6 | 5015452523321 |
7 | 536444061415 |
oct | 121765141401 |
9 | 31354108844 |
10 | 11003020033 |
11 | 4736a10895 |
12 | 2170a80541 |
13 | 1064744155 |
14 | 765458d45 |
15 | 445e8913d |
hex | 28fd4c301 |
11003020033 has 2 divisors, whose sum is σ = 11003020034. Its totient is φ = 11003020032.
The previous prime is 11003020013. The next prime is 11003020043. The reversal of 11003020033 is 33002030011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10837434609 + 165585424 = 104103^2 + 12868^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11003020033 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11003019995 and 11003020022.
It is not a weakly prime, because it can be changed into another prime (11003020013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5501510016 + 5501510017.
It is an arithmetic number, because the mean of its divisors is an integer number (5501510017).
Almost surely, 211003020033 is an apocalyptic number.
It is an amenable number.
11003020033 is a deficient number, since it is larger than the sum of its proper divisors (1).
11003020033 is an equidigital number, since it uses as much as digits as its factorization.
11003020033 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 13.
Adding to 11003020033 its reverse (33002030011), we get a palindrome (44005050044).
The spelling of 11003020033 in words is "eleven billion, three million, twenty thousand, thirty-three".
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