Base | Representation |
---|---|
bin | 110011001111001001… |
… | …1111101001111110011 |
3 | 101112000012021000100222 |
4 | 1212132103331033303 |
5 | 3300320213323011 |
6 | 122314105203255 |
7 | 10643436250205 |
oct | 1463623751763 |
9 | 345005230328 |
10 | 110030214131 |
11 | 42733207472 |
12 | 193a8a9052b |
13 | a4b68484a6 |
14 | 547b20a775 |
15 | 2cdeab4ddb |
hex | 199e4fd3f3 |
110030214131 has 2 divisors, whose sum is σ = 110030214132. Its totient is φ = 110030214130.
The previous prime is 110030214121. The next prime is 110030214191. The reversal of 110030214131 is 131412030011.
It is a weak prime.
It is an emirp because it is prime and its reverse (131412030011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 110030214131 - 218 = 110029951987 is a prime.
It is a super-2 number, since 2×1100302141312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (110030214121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55015107065 + 55015107066.
It is an arithmetic number, because the mean of its divisors is an integer number (55015107066).
Almost surely, 2110030214131 is an apocalyptic number.
110030214131 is a deficient number, since it is larger than the sum of its proper divisors (1).
110030214131 is an equidigital number, since it uses as much as digits as its factorization.
110030214131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 110030214131 its reverse (131412030011), we get a palindrome (241442244142).
The spelling of 110030214131 in words is "one hundred ten billion, thirty million, two hundred fourteen thousand, one hundred thirty-one".
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