Base | Representation |
---|---|
bin | 10100011111101011… |
… | …00011001001000111 |
3 | 1001101211022002220210 |
4 | 22033311203021013 |
5 | 140013244122210 |
6 | 5015454530503 |
7 | 536444632503 |
oct | 121765431107 |
9 | 31354262823 |
10 | 11003114055 |
11 | 4736a7549a |
12 | 2170b06a33 |
13 | 1064777b9b |
14 | 765481303 |
15 | 445ea6e20 |
hex | 28fd63247 |
11003114055 has 32 divisors (see below), whose sum is σ = 17921018880. Its totient is φ = 5763859200.
The previous prime is 11003114041. The next prime is 11003114093. The reversal of 11003114055 is 55041130011.
It is a happy number.
It is not a de Polignac number, because 11003114055 - 223 = 10994725447 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 174294 + ... + 228876.
It is an arithmetic number, because the mean of its divisors is an integer number (560031840).
Almost surely, 211003114055 is an apocalyptic number.
11003114055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11003114055 is a deficient number, since it is larger than the sum of its proper divisors (6917904825).
11003114055 is a wasteful number, since it uses less digits than its factorization.
11003114055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 54831.
The product of its (nonzero) digits is 300, while the sum is 21.
Adding to 11003114055 its reverse (55041130011), we get a palindrome (66044244066).
It can be divided in two parts, 110031140 and 55, that added together give a triangular number (110031195 = T14834).
The spelling of 11003114055 in words is "eleven billion, three million, one hundred fourteen thousand, fifty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.086 sec. • engine limits •