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11003133133 = 49922050367
BaseRepresentation
bin10100011111101011…
…00111110011001101
31001101211100002002101
422033311213303031
5140013300230013
65015455155101
7536445042226
oct121765476315
931354302071
1011003133133
114736a88863
122170b15a91
131064783785
1476548824d
15445eac8dd
hex28fd67ccd

11003133133 has 4 divisors (see below), whose sum is σ = 11025184000. Its totient is φ = 10981082268.

The previous prime is 11003133121. The next prime is 11003133137. The reversal of 11003133133 is 33133130011.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11003133133 - 217 = 11003002061 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11003133133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11003133137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11024685 + ... + 11025682.

It is an arithmetic number, because the mean of its divisors is an integer number (2756296000).

Almost surely, 211003133133 is an apocalyptic number.

It is an amenable number.

11003133133 is a deficient number, since it is larger than the sum of its proper divisors (22050867).

11003133133 is an equidigital number, since it uses as much as digits as its factorization.

11003133133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22050866.

The product of its (nonzero) digits is 243, while the sum is 19.

Adding to 11003133133 its reverse (33133130011), we get a palindrome (44136263144).

The spelling of 11003133133 in words is "eleven billion, three million, one hundred thirty-three thousand, one hundred thirty-three".

Divisors: 1 499 22050367 11003133133