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11003201222003 = 29959367275317
BaseRepresentation
bin1010000000011110000111…
…1001100111010101110011
31102221220012000022121100022
42200013201321213111303
52420234024003101003
635222444552514055
72213645404133144
oct240074171472563
942856160277308
1011003201222003
113562482267431
1212985b19ab92b
1361a79c6ccb63
142a07b479bacb
15141342749738
hexa01e1e67573

11003201222003 has 4 divisors (see below), whose sum is σ = 11003568527280. Its totient is φ = 11002833916728.

The previous prime is 11003201221981. The next prime is 11003201222047. The reversal of 11003201222003 is 30022210230011.

11003201222003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11003201222003 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11003201222063) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 183607700 + ... + 183667617.

It is an arithmetic number, because the mean of its divisors is an integer number (2750892131820).

Almost surely, 211003201222003 is an apocalyptic number.

11003201222003 is a deficient number, since it is larger than the sum of its proper divisors (367305277).

11003201222003 is an equidigital number, since it uses as much as digits as its factorization.

11003201222003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 367305276.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 11003201222003 its reverse (30022210230011), we get a palindrome (41025411452014).

The spelling of 11003201222003 in words is "eleven trillion, three billion, two hundred one million, two hundred twenty-two thousand, three".

Divisors: 1 29959 367275317 11003201222003