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110032234411417 is a prime number
BaseRepresentation
bin11001000001001011100000…
…001111101111010110011001
3112102120222102121021112201121
4121001023200033233112121
5103410232004002131132
61030004035523045241
732114365225505443
oct3101134017572631
9472528377245647
10110032234411417
113207245487762a
1210410b98810821
134951cc2555a96
141d25835023493
15cac2ce5a4497
hex6412e03ef599

110032234411417 has 2 divisors, whose sum is σ = 110032234411418. Its totient is φ = 110032234411416.

The previous prime is 110032234411373. The next prime is 110032234411447. The reversal of 110032234411417 is 714114432230011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 63518524962201 + 46513709449216 = 7969851^2 + 6820096^2 .

It is a cyclic number.

It is not a de Polignac number, because 110032234411417 - 211 = 110032234409369 is a prime.

It is not a weakly prime, because it can be changed into another prime (110032234411447) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55016117205708 + 55016117205709.

It is an arithmetic number, because the mean of its divisors is an integer number (55016117205709).

Almost surely, 2110032234411417 is an apocalyptic number.

It is an amenable number.

110032234411417 is a deficient number, since it is larger than the sum of its proper divisors (1).

110032234411417 is an equidigital number, since it uses as much as digits as its factorization.

110032234411417 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16128, while the sum is 34.

Adding to 110032234411417 its reverse (714114432230011), we get a palindrome (824146666641428).

The spelling of 110032234411417 in words is "one hundred ten trillion, thirty-two billion, two hundred thirty-four million, four hundred eleven thousand, four hundred seventeen".