110033000130000 has 200 divisors, whose sum is σ = 355212929202208. Its totient is φ = 29341164096000.

The previous prime is 110033000129993. The next prime is 110033000130047. The reversal of 110033000130000 is 31000330011.

It is a tau number, because it is divible by the number of its divisors (200).

It is a super-2 number, since 2×110033000130000² (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 1773178974 + ... + 1773241026.

Almost surely, 2^{110033000130000} is an apocalyptic number.

110033000130000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 110033000130000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (177606464601104).

110033000130000 is an abundant number, since it is smaller than the sum of its proper divisors (245179929072208).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

110033000130000 is an equidigital number, since it uses as much as digits as its factorization.

110033000130000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 121191 (or 121170 counting only the distinct ones).

The product of its (nonzero) digits is 27, while the sum is 12.

Adding to 110033000130000 its reverse (31000330011), we get a palindrome (110064000460011).

The spelling of 110033000130000 in words is "one hundred ten trillion, thirty-three billion, one hundred thirty thousand".