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110033101133 is a prime number
BaseRepresentation
bin110011001111001111…
…0111110000101001101
3101112000101200200120222
41212132132332011031
53300321433214013
6122314251121125
710643502633134
oct1463636760515
9345011620528
10110033101133
11427348a951a
12193a9a431a5
13a4b7319587
14547b75c91b
152cdee85508
hex199e7be14d

110033101133 has 2 divisors, whose sum is σ = 110033101134. Its totient is φ = 110033101132.

The previous prime is 110033101121. The next prime is 110033101141. The reversal of 110033101133 is 331101330011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 107989789924 + 2043311209 = 328618^2 + 45203^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-110033101133 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110033103133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55016550566 + 55016550567.

It is an arithmetic number, because the mean of its divisors is an integer number (55016550567).

Almost surely, 2110033101133 is an apocalyptic number.

It is an amenable number.

110033101133 is a deficient number, since it is larger than the sum of its proper divisors (1).

110033101133 is an equidigital number, since it uses as much as digits as its factorization.

110033101133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 110033101133 its reverse (331101330011), we get a palindrome (441134431144).

It can be divided in two parts, 11003 and 3101133, that added together give a cube (3112136 = 1463).

The spelling of 110033101133 in words is "one hundred ten billion, thirty-three million, one hundred one thousand, one hundred thirty-three".