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1100331101023 = 71121299092209
BaseRepresentation
bin10000000000110000110…
…110000010101101011111
310220012010222002102221121
4100000300312002231133
5121011434230213043
62201252442111411
7142332142016440
oct20006066025537
93805128072847
101100331101023
11394714248100
121593027ab567
137c9b757523b
143b3834552c7
151d94eaa4ded
hex10030d82b5f

1100331101023 has 12 divisors (see below), whose sum is σ = 1382234111440. Its totient is φ = 857400857280.

The previous prime is 1100331101003. The next prime is 1100331101087. The reversal of 1100331101023 is 3201011330011.

It is not a de Polignac number, because 1100331101023 - 25 = 1100331100991 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1100331100988 and 1100331101006.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1100331101003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 649545258 + ... + 649546951.

Almost surely, 21100331101023 is an apocalyptic number.

1100331101023 is a deficient number, since it is larger than the sum of its proper divisors (281903010417).

1100331101023 is a wasteful number, since it uses less digits than its factorization.

1100331101023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1299092238 (or 1299092227 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 1100331101023 its reverse (3201011330011), we get a palindrome (4301342431034).

The spelling of 1100331101023 in words is "one trillion, one hundred billion, three hundred thirty-one million, one hundred one thousand, twenty-three".

Divisors: 1 7 11 77 121 847 1299092209 9093645463 14290014299 100030100093 157190157289 1100331101023