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1100331322133 is a prime number
BaseRepresentation
bin10000000000110000110…
…110111000101100010101
310220012010222111200020212
4100000300312320230111
5121011434304302013
62201252450535205
7142332143630201
oct20006066705425
93805128450225
101100331322133
1139471438923a
12159302897505
137c9b7621a84
143b3834b1b01
151d94eaea6a8
hex10030db8b15

1100331322133 has 2 divisors, whose sum is σ = 1100331322134. Its totient is φ = 1100331322132.

The previous prime is 1100331322117. The next prime is 1100331322151. The reversal of 1100331322133 is 3312231330011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 826066489924 + 274264832209 = 908882^2 + 523703^2 .

It is an emirp because it is prime and its reverse (3312231330011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1100331322133 - 24 = 1100331322117 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1100331322099 and 1100331322108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1100331322633) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550165661066 + 550165661067.

It is an arithmetic number, because the mean of its divisors is an integer number (550165661067).

Almost surely, 21100331322133 is an apocalyptic number.

It is an amenable number.

1100331322133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100331322133 is an equidigital number, since it uses as much as digits as its factorization.

1100331322133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 1100331322133 its reverse (3312231330011), we get a palindrome (4412562652144).

The spelling of 1100331322133 in words is "one trillion, one hundred billion, three hundred thirty-one million, three hundred twenty-two thousand, one hundred thirty-three".