1100332140341 has 4 divisors (see below), whose sum is σ = 1257522446112. Its totient is φ = 943141834572.

The previous prime is 1100332140317. The next prime is 1100332140359. The reversal of 1100332140341 is 1430412330011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1100332140341 - 2¹⁸ = 1100331878197 is a prime.

It is a super-2 number, since 2×1100332140341² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1100332140311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 78595152875 + ... + 78595152888.

It is an arithmetic number, because the mean of its divisors is an integer number (314380611528).

Almost surely, 2^{1100332140341} is an apocalyptic number.

It is an amenable number.

1100332140341 is a deficient number, since it is larger than the sum of its proper divisors (157190305771).

1100332140341 is an equidigital number, since it uses as much as digits as its factorization.

1100332140341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 157190305770.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 1100332140341 its reverse (1430412330011), we get a palindrome (2530744470352).

The spelling of 1100332140341 in words is "one trillion, one hundred billion, three hundred thirty-two million, one hundred forty thousand, three hundred forty-one".