1100332497749 has 2 divisors, whose sum is σ = 1100332497750. Its totient is φ = 1100332497748.

The previous prime is 1100332497743. The next prime is 1100332497751. The reversal of 1100332497749 is 9477942330011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 969781800625 + 130550697124 = 984775^2 + 361318^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100332497749 - 2¹² = 1100332493653 is a prime.

Together with 1100332497751, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1100332497697 and 1100332497706.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1100332497743) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550166248874 + 550166248875.

It is an arithmetic number, because the mean of its divisors is an integer number (550166248875).

Almost surely, 2^{1100332497749} is an apocalyptic number.

It is an amenable number.

1100332497749 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100332497749 is an equidigital number, since it uses as much as digits as its factorization.

1100332497749 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1143072, while the sum is 50.

The spelling of 1100332497749 in words is "one trillion, one hundred billion, three hundred thirty-two million, four hundred ninety-seven thousand, seven hundred forty-nine".