Base | Representation |
---|---|
bin | 110011001111010010… |
… | …0011011111101101101 |
3 | 101112000111101111110111 |
4 | 1212132210123331231 |
5 | 3300322320044003 |
6 | 122314341540021 |
7 | 10643521052260 |
oct | 1463644337555 |
9 | 345014344414 |
10 | 110034534253 |
11 | 42735698216 |
12 | 193aa414611 |
13 | a4b76cb987 |
14 | 547ba12cd7 |
15 | 2ce0169e6d |
hex | 199e91bf6d |
110034534253 has 4 divisors (see below), whose sum is σ = 125753753440. Its totient is φ = 94315315068.
The previous prime is 110034534229. The next prime is 110034534293. The reversal of 110034534253 is 352435430011.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 110034534253 - 213 = 110034526061 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (110034534293) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7859609583 + ... + 7859609596.
It is an arithmetic number, because the mean of its divisors is an integer number (31438438360).
Almost surely, 2110034534253 is an apocalyptic number.
It is an amenable number.
110034534253 is a deficient number, since it is larger than the sum of its proper divisors (15719219187).
110034534253 is an equidigital number, since it uses as much as digits as its factorization.
110034534253 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15719219186.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 110034534253 its reverse (352435430011), we get a palindrome (462469964264).
The spelling of 110034534253 in words is "one hundred ten billion, thirty-four million, five hundred thirty-four thousand, two hundred fifty-three".
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