1100400403 has 4 divisors (see below), whose sum is σ = 1100467728. Its totient is φ = 1100333080.

The previous prime is 1100400383. The next prime is 1100400407. The reversal of 1100400403 is 3040040011.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 3040040011 = 17 ⋅178825883.

It is a cyclic number.

It is not a de Polignac number, because 1100400403 - 2²¹ = 1098303251 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1100400407) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8250 + ... + 47632.

It is an arithmetic number, because the mean of its divisors is an integer number (275116932).

Almost surely, 2^1100400403 is an apocalyptic number.

1100400403 is a deficient number, since it is larger than the sum of its proper divisors (67325).

1100400403 is an equidigital number, since it uses as much as digits as its factorization.

1100400403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 67324.

The product of its (nonzero) digits is 48, while the sum is 13.

The square root of 1100400403 is about 33172.2836566915. The cubic root of 1100400403 is about 1032.4053511880.

Adding to 1100400403 its reverse (3040040011), we get a palindrome (4140440414).

The spelling of 1100400403 in words is "one billion, one hundred million, four hundred thousand, four hundred three".