Base | Representation |
---|---|
bin | 10100011111110010… |
… | …10111000110010111 |
3 | 1001101220011212121222 |
4 | 22033321113012113 |
5 | 140014023111203 |
6 | 5015532200555 |
7 | 536456263661 |
oct | 121771270627 |
9 | 31356155558 |
10 | 11004113303 |
11 | 4737598217 |
12 | 217130915b |
13 | 1064a37961 |
14 | 765661531 |
15 | 446103038 |
hex | 28fe57197 |
11004113303 has 2 divisors, whose sum is σ = 11004113304. Its totient is φ = 11004113302.
The previous prime is 11004113297. The next prime is 11004113327. The reversal of 11004113303 is 30331140011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11004113303 - 214 = 11004096919 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11004113363) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5502056651 + 5502056652.
It is an arithmetic number, because the mean of its divisors is an integer number (5502056652).
Almost surely, 211004113303 is an apocalyptic number.
11004113303 is a deficient number, since it is larger than the sum of its proper divisors (1).
11004113303 is an equidigital number, since it uses as much as digits as its factorization.
11004113303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 11004113303 its reverse (30331140011), we get a palindrome (41335253314).
The spelling of 11004113303 in words is "eleven billion, four million, one hundred thirteen thousand, three hundred three".
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