11004113387 has 2 divisors, whose sum is σ = 11004113388. Its totient is φ = 11004113386.

The previous prime is 11004113383. The next prime is 11004113453. The reversal of 11004113387 is 78331140011.

It is a weak prime.

It is an emirp because it is prime and its reverse (78331140011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11004113387 - 2² = 11004113383 is a prime.

It is a super-2 number, since 2×11004113387² (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11004113381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5502056693 + 5502056694.

It is an arithmetic number, because the mean of its divisors is an integer number (5502056694).

Almost surely, 2^11004113387 is an apocalyptic number.

11004113387 is a deficient number, since it is larger than the sum of its proper divisors (1).

11004113387 is an equidigital number, since it uses as much as digits as its factorization.

11004113387 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2016, while the sum is 29.

Adding to 11004113387 its reverse (78331140011), we get a palindrome (89335253398).

The spelling of 11004113387 in words is "eleven billion, four million, one hundred thirteen thousand, three hundred eighty-seven".