11004113453 has 2 divisors, whose sum is σ = 11004113454. Its totient is φ = 11004113452.

The previous prime is 11004113387. The next prime is 11004113503. The reversal of 11004113453 is 35431140011.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6815823364 + 4188290089 = 82558^2 + 64717^2 .

It is a cyclic number.

It is not a de Polignac number, because 11004113453 - 2¹⁶ = 11004047917 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11004613453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5502056726 + 5502056727.

It is an arithmetic number, because the mean of its divisors is an integer number (5502056727).

Almost surely, 2^11004113453 is an apocalyptic number.

It is an amenable number.

11004113453 is a deficient number, since it is larger than the sum of its proper divisors (1).

11004113453 is an equidigital number, since it uses as much as digits as its factorization.

11004113453 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 720, while the sum is 23.

Adding to 11004113453 its reverse (35431140011), we get a palindrome (46435253464).

The spelling of 11004113453 in words is "eleven billion, four million, one hundred thirteen thousand, four hundred fifty-three".