Base | Representation |
---|---|
bin | 10100011111110010… |
… | …10111001000011001 |
3 | 1001101220011212210210 |
4 | 22033321113020121 |
5 | 140014023112213 |
6 | 5015532201333 |
7 | 536456264235 |
oct | 121771271031 |
9 | 31356155723 |
10 | 11004113433 |
11 | 4737598325 |
12 | 2171309249 |
13 | 1064a37a31 |
14 | 7656615c5 |
15 | 4461030c3 |
hex | 28fe57219 |
11004113433 has 16 divisors (see below), whose sum is σ = 14900809536. Its totient is φ = 7221888960.
The previous prime is 11004113387. The next prime is 11004113453. The reversal of 11004113433 is 33431140011.
It is not a de Polignac number, because 11004113433 - 29 = 11004112921 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11004113453) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 307243 + ... + 341183.
It is an arithmetic number, because the mean of its divisors is an integer number (931300596).
Almost surely, 211004113433 is an apocalyptic number.
It is an amenable number.
11004113433 is a deficient number, since it is larger than the sum of its proper divisors (3896696103).
11004113433 is a wasteful number, since it uses less digits than its factorization.
11004113433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 35624.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 11004113433 its reverse (33431140011), we get a palindrome (44435253444).
The spelling of 11004113433 in words is "eleven billion, four million, one hundred thirteen thousand, four hundred thirty-three".
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