Base | Representation |
---|---|
bin | 110011001111011111… |
… | …1000001100100110101 |
3 | 101112000222111121020020 |
4 | 1212132333001210311 |
5 | 3300331111112203 |
6 | 122315151155353 |
7 | 10643634231345 |
oct | 1463677014465 |
9 | 345028447206 |
10 | 110041504053 |
11 | 42739618788 |
12 | 193b0815b59 |
13 | a4b8c9c210 |
14 | 547c908d25 |
15 | 2ce0a95153 |
hex | 199efc1935 |
110041504053 has 16 divisors (see below), whose sum is σ = 158038574400. Its totient is φ = 67704879744.
The previous prime is 110041504003. The next prime is 110041504081. The reversal of 110041504053 is 350405140011.
It is a happy number.
It is not a de Polignac number, because 110041504053 - 216 = 110041438517 is a prime.
It is a super-2 number, since 2×1100415040532 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (110041504003) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 61903 + ... + 473196.
It is an arithmetic number, because the mean of its divisors is an integer number (9877410900).
Almost surely, 2110041504053 is an apocalyptic number.
110041504053 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
110041504053 is a deficient number, since it is larger than the sum of its proper divisors (47997070347).
110041504053 is a wasteful number, since it uses less digits than its factorization.
110041504053 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 540388.
The product of its (nonzero) digits is 1200, while the sum is 24.
Adding to 110041504053 its reverse (350405140011), we get a palindrome (460446644064).
The spelling of 110041504053 in words is "one hundred ten billion, forty-one million, five hundred four thousand, fifty-three".
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