Base | Representation |
---|---|
bin | 10000000000110110111… |
… | …011001011010110011000 |
3 | 10220012102002001001112120 |
4 | 100000312323023112120 |
5 | 121012141334013144 |
6 | 2201310524341240 |
7 | 142334521051104 |
oct | 20006673132630 |
9 | 3805362031476 |
10 | 1100433110424 |
11 | 39476689129a |
12 | 1593309a4820 |
13 | 7ca0274052b |
14 | 3b392c0a904 |
15 | 1d958a04e19 |
hex | 10036ecb598 |
1100433110424 has 32 divisors (see below), whose sum is σ = 2751166218240. Its totient is φ = 366799911200.
The previous prime is 1100433110311. The next prime is 1100433110437. The reversal of 1100433110424 is 4240113340011.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is a junction number, because it is equal to n+sod(n) for n = 1100433110394 and 1100433110403.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 132529 + ... + 1489439.
It is an arithmetic number, because the mean of its divisors is an integer number (85973944320).
Almost surely, 21100433110424 is an apocalyptic number.
It is an amenable number.
1100433110424 is an abundant number, since it is smaller than the sum of its proper divisors (1650733107816).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1100433110424 is a wasteful number, since it uses less digits than its factorization.
1100433110424 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1390711 (or 1390707 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 1100433110424 its reverse (4240113340011), we get a palindrome (5340546450435).
The spelling of 1100433110424 in words is "one trillion, one hundred billion, four hundred thirty-three million, one hundred ten thousand, four hundred twenty-four".
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