11004331223399 has 2 divisors, whose sum is σ = 11004331223400. Its totient is φ = 11004331223398.

The previous prime is 11004331223311. The next prime is 11004331223419. The reversal of 11004331223399 is 99332213340011.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11004331223399 is a prime.

It is a super-2 number, since 2×11004331223399² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11004331223999) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5502165611699 + 5502165611700.

It is an arithmetic number, because the mean of its divisors is an integer number (5502165611700).

Almost surely, 2^{11004331223399} is an apocalyptic number.

11004331223399 is a deficient number, since it is larger than the sum of its proper divisors (1).

11004331223399 is an equidigital number, since it uses as much as digits as its factorization.

11004331223399 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 104976, while the sum is 41.

The spelling of 11004331223399 in words is "eleven trillion, four billion, three hundred thirty-one million, two hundred twenty-three thousand, three hundred ninety-nine".