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1100434434230 = 25331332457533
BaseRepresentation
bin10000000000110111000…
…000001110100010110110
310220012102011112022110102
4100000313000032202312
5121012142203343410
62201311012554102
7142334535233435
oct20006700164266
93805364468412
101100434434230
1139476760594a
12159331322932
137ca02ab4c51
143b39307311c
151d958bb72a5
hex1003700e8b6

1100434434230 has 16 divisors (see below), whose sum is σ = 1986766223184. Its totient is φ = 438843942240.

The previous prime is 1100434434227. The next prime is 1100434434263. The reversal of 1100434434230 is 324344340011.

It is a happy number.

It is a super-4 number, since 4×11004344342304 (a number of 49 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1100434434193 and 1100434434202.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 166225457 + ... + 166232076.

It is an arithmetic number, because the mean of its divisors is an integer number (124172888949).

Almost surely, 21100434434230 is an apocalyptic number.

1100434434230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1100434434230 is a deficient number, since it is larger than the sum of its proper divisors (886331788954).

1100434434230 is a wasteful number, since it uses less digits than its factorization.

1100434434230 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 332457871.

The product of its (nonzero) digits is 13824, while the sum is 29.

Adding to 1100434434230 its reverse (324344340011), we get a palindrome (1424778774241).

The spelling of 1100434434230 in words is "one trillion, one hundred billion, four hundred thirty-four million, four hundred thirty-four thousand, two hundred thirty".

Divisors: 1 2 5 10 331 662 1655 3310 332457533 664915066 1662287665 3324575330 110043443423 220086886846 550217217115 1100434434230