Base | Representation |
---|---|
bin | 10100011111110101… |
… | …00010000000101111 |
3 | 1001101220202110112102 |
4 | 22033322202000233 |
5 | 140014112421033 |
6 | 5015542525315 |
7 | 536462012363 |
oct | 121772420057 |
9 | 31356673472 |
10 | 11004420143 |
11 | 4737787802 |
12 | 217143683b |
13 | 1064b14512 |
14 | 7657012a3 |
15 | 446163de8 |
hex | 28fea202f |
11004420143 has 8 divisors (see below), whose sum is σ = 11207323296. Its totient is φ = 10802848000.
The previous prime is 11004420071. The next prime is 11004420149. The reversal of 11004420143 is 34102440011.
11004420143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11004420143 - 214 = 11004403759 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11004420149) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 316058 + ... + 349143.
It is an arithmetic number, because the mean of its divisors is an integer number (1400915412).
Almost surely, 211004420143 is an apocalyptic number.
11004420143 is a deficient number, since it is larger than the sum of its proper divisors (202903153).
11004420143 is an equidigital number, since it uses as much as digits as its factorization.
11004420143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 665505.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 11004420143 its reverse (34102440011), we get a palindrome (45106860154).
The spelling of 11004420143 in words is "eleven billion, four million, four hundred twenty thousand, one hundred forty-three".
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