Base | Representation |
---|---|
bin | 110011001111100100… |
… | …1011101100010000001 |
3 | 101112001011122121020122 |
4 | 1212133021131202001 |
5 | 3300332311140001 |
6 | 122315325550025 |
7 | 10643666415023 |
oct | 1463711354201 |
9 | 345034577218 |
10 | 110044240001 |
11 | 427401172a3 |
12 | 193b1715315 |
13 | a4b9719617 |
14 | 547d01c013 |
15 | 2ce0e35b1b |
hex | 199f25d881 |
110044240001 has 2 divisors, whose sum is σ = 110044240002. Its totient is φ = 110044240000.
The previous prime is 110044239989. The next prime is 110044240003. The reversal of 110044240001 is 100042440011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 85567950400 + 24476289601 = 292520^2 + 156449^2 .
It is an emirp because it is prime and its reverse (100042440011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 110044240001 - 222 = 110040045697 is a prime.
Together with 110044240003, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (110044240003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55022120000 + 55022120001.
It is an arithmetic number, because the mean of its divisors is an integer number (55022120001).
Almost surely, 2110044240001 is an apocalyptic number.
It is an amenable number.
110044240001 is a deficient number, since it is larger than the sum of its proper divisors (1).
110044240001 is an equidigital number, since it uses as much as digits as its factorization.
110044240001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 128, while the sum is 17.
Adding to 110044240001 its reverse (100042440011), we get a palindrome (210086680012).
The spelling of 110044240001 in words is "one hundred ten billion, forty-four million, two hundred forty thousand, one".
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