Base | Representation |
---|---|
bin | 101001111110… |
… | …101100101001 |
3 | 202201002121222 |
4 | 221332230221 |
5 | 10304122323 |
6 | 1031511425 |
7 | 162352466 |
oct | 51765451 |
9 | 22632558 |
10 | 11004713 |
11 | 6237005 |
12 | 3828575 |
13 | 2383c85 |
14 | 166666d |
15 | e759c8 |
hex | a7eb29 |
11004713 has 2 divisors, whose sum is σ = 11004714. Its totient is φ = 11004712.
The previous prime is 11004701. The next prime is 11004727. The reversal of 11004713 is 31740011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9078169 + 1926544 = 3013^2 + 1388^2 .
It is an emirp because it is prime and its reverse (31740011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11004713 - 222 = 6810409 is a prime.
It is a super-2 number, since 2×110047132 = 242207416424738, which contains 22 as substring.
It is a Chen prime.
It is a plaindrome in base 14.
It is a junction number, because it is equal to n+sod(n) for n = 11004691 and 11004700.
It is not a weakly prime, because it can be changed into another prime (11004793) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5502356 + 5502357.
It is an arithmetic number, because the mean of its divisors is an integer number (5502357).
Almost surely, 211004713 is an apocalyptic number.
It is an amenable number.
11004713 is a deficient number, since it is larger than the sum of its proper divisors (1).
11004713 is an equidigital number, since it uses as much as digits as its factorization.
11004713 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 84, while the sum is 17.
The square root of 11004713 is about 3317.3352257497. The cubic root of 11004713 is about 222.4297670010.
Adding to 11004713 its reverse (31740011), we get a palindrome (42744724).
The spelling of 11004713 in words is "eleven million, four thousand, seven hundred thirteen".
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