11004923 has 2 divisors, whose sum is σ = 11004924. Its totient is φ = 11004922.

The previous prime is 11004901. The next prime is 11004943. The reversal of 11004923 is 32940011.

It is an a-pointer prime, because the next prime (11004943) can be obtained adding 11004923 to its sum of digits (20).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11004923 - 2¹⁰ = 11003899 is a prime.

It is a super-2 number, since 2×11004923² = 242216660471858, which contains 22 as substring.

It is a plaindrome in base 14.

It is a junction number, because it is equal to n+sod(n) for n = 11004895 and 11004904.

It is not a weakly prime, because it can be changed into another prime (11004943) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5502461 + 5502462.

It is an arithmetic number, because the mean of its divisors is an integer number (5502462).

Almost surely, 2^11004923 is an apocalyptic number.

11004923 is a deficient number, since it is larger than the sum of its proper divisors (1).

11004923 is an equidigital number, since it uses as much as digits as its factorization.

11004923 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 20.

The square root of 11004923 is about 3317.3668775099. The cubic root of 11004923 is about 222.4311818480.

Adding to 11004923 its reverse (32940011), we get a palindrome (43944934).

The spelling of 11004923 in words is "eleven million, four thousand, nine hundred twenty-three".