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11005055501207 is a prime number
BaseRepresentation
bin1010000000100101000001…
…1011001000001110010111
31102222001222020110202012212
42200021100123020032113
52420301323202014312
635223352552304035
72214042351220025
oct240112033101627
942861866422185
1011005055501207
113563243a24889
121298a2a9a201b
1361aa06915ca1
142a090cb63715
15141400425822
hexa02506c8397

11005055501207 has 2 divisors, whose sum is σ = 11005055501208. Its totient is φ = 11005055501206.

The previous prime is 11005055501107. The next prime is 11005055501221. The reversal of 11005055501207 is 70210555050011.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11005055501207 - 28 = 11005055500951 is a prime.

It is a super-2 number, since 2×110050555012072 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11005055501107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5502527750603 + 5502527750604.

It is an arithmetic number, because the mean of its divisors is an integer number (5502527750604).

Almost surely, 211005055501207 is an apocalyptic number.

11005055501207 is a deficient number, since it is larger than the sum of its proper divisors (1).

11005055501207 is an equidigital number, since it uses as much as digits as its factorization.

11005055501207 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8750, while the sum is 32.

The spelling of 11005055501207 in words is "eleven trillion, five billion, fifty-five million, five hundred one thousand, two hundred seven".