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110055136153 = 1924321133601
BaseRepresentation
bin110011001111111001…
…1000001101110011001
3101112001221011011221211
41212133303001232121
53300343103324103
6122320355303121
710644161136154
oct1463763015631
9345057134854
10110055136153
1142746289786
12193b52aaaa1
13a4bba63051
145480656c9b
152ce1d8936d
hex199fcc1b99

110055136153 has 24 divisors (see below), whose sum is σ = 119420432736. Its totient is φ = 101352384000.

The previous prime is 110055136141. The next prime is 110055136189. The reversal of 110055136153 is 351631550011.

It is a happy number.

It is not a de Polignac number, because 110055136153 - 221 = 110053039001 is a prime.

It is a super-2 number, since 2×1100551361532 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (110055136123) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3258553 + ... + 3292153.

It is an arithmetic number, because the mean of its divisors is an integer number (4975851364).

Almost surely, 2110055136153 is an apocalyptic number.

It is an amenable number.

110055136153 is a deficient number, since it is larger than the sum of its proper divisors (9365296583).

110055136153 is a wasteful number, since it uses less digits than its factorization.

110055136153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33893 (or 33874 counting only the distinct ones).

The product of its (nonzero) digits is 6750, while the sum is 31.

Adding to 110055136153 its reverse (351631550011), we get a palindrome (461686686164).

The spelling of 110055136153 in words is "one hundred ten billion, fifty-five million, one hundred thirty-six thousand, one hundred fifty-three".

Divisors: 1 19 43 211 361 817 4009 9073 15523 33601 76171 172387 638419 1444843 3275353 7089811 12129961 27452017 134706409 304861873 521588323 2559421771 5792375587 110055136153